To verify put x = 1 and y = 2 in given equations, and check wheater LHS and RHS are equal (i) x 3 y 3 = ( x y ) ( x 2 − x y y 2 ) LHS x 3 y 3 = 1 3 2 3 = 9If f (x, y) = x 3 y – xy 3, then what is the value of \(\left {\frac{1}{{\frac{{{\rm{df}}}}{{{\rm{dx}}}}}{\rm{\;}} \frac{1}{{\frac{{{\rm{df}}}}{{{\rm{dy}}}}Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge and
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F x y f x f y f 3 3-Y y • x y = — = ————— 1 x Equivalent fraction The fraction thus generated looks different but has the same value as the whole Common denominator The equivalent fraction and the other fraction involved in the calculation share the same denominatorHandwritten continued fraction theorems {y x = 1, y x = 3} intersecting lines ;
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2xy=3 Geometric figure Straight Line Slope = 2 xintercept = 3/2 = yintercept = 3/1 = Rearrange Rearrange the equation by subtracting what is to the right of theInput Solution Stepbystep solution;2*(xy)(8*(y^3x^3))=0 Step 1 Trying to factor as a Difference of Cubes 11 Factoring y 3x 3 Theory A difference of two perfect cubes, a 3 b 3 can be factored into (ab) • (a 2 ab b 2) Proof (ab)•(a 2 abb 2) = a 3 a 2 b ab 2ba 2b 2 ab 3 = a 3 (a 2 bba 2)(ab 2b 2 a)b 3 = a 3 0 0b 3 = a 3b 3 Check y 3 is
X(y3)=0 Step 1 Equation of a Straight Line 11 Solve xy3 = 0 Tiger recognizes that we have here an equation of a straight line Such an equation is usually written y=mxb ("y=mxc" in the UK) "y=mxb" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis x = 1 and y = 4 Another method which will work well in this case is to equate two equal expressions This is a form of substitution Transpose both equations to give y = equ 1 y = x 3" and " equ 2 y = 7x 3 Note that " " y = y Therefore 7x 3 = x 3 " " 6x = 6 " "x = 1 Equ 1 y = 1 3 rArr y = 4Solution (xy)^2 =(xy)(xy) Then you FOIL (First, outer, inner, last) (xy)^2=(xy)(xy) = xx xy xy yy and when you combine like terms = x^2 2xy y^2 (x
Plot of solution set Alternate forms Download Page POWERED BY THE WOLFRAM LANGUAGE Related Queries parallel lines ;Answer by lenny460 (1073) ( Show Source ) You can put this solution on YOUR website!Simplify (xy)^3 (x − y)3 ( x y) 3 Use the Binomial Theorem x3 3x2(−y) 3x(−y)2 (−y)3 x 3 3 x 2 ( y) 3 x ( y) 2 ( y) 3 Simplify each term Tap for more steps Rewrite using the commutative property of multiplication
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Factor x y x y out of − x y 3 x y 3 Factor x y x y out of x y ( x 2) x y ( − 1 y 2) x y ( x 2) x y ( 1 y 2) Factor Tap for more steps Since both terms are perfect squares, factor using the difference of squares formula, a 2 − b 2 = ( a b) ( a − b) a 2 b 2 = ( a b) ( a b) where a = x a = x and b = y b = yFactor (xy)^3 (xy)^3 (x y)3 (x − y)3 ( x y) 3 ( x y) 3 Since both terms are perfect cubes, factor using the sum of cubes formula, a3 b3 = (ab)(a2 −abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = x y a = x y and b = x− y b = x yX y = 1, x y = 3 Extended Keyboard;
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Y = x^3 x, y = 3xSketch the region enclosed by the given curves Decidewhether to integrate with respect to x or y Draw a typical approximatingrectangle aY = x − 3 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side x3=y x − 3 = y Add 3 to both sides Add 3 to both sides x=y3 x = y 3Solve for x x\in \mathrm {R} x ∈ R View solution steps Solution Steps x ^ { 3 } y ^ { 3 } = ( x y ) ( x ^ { 2 } x y y ^ { 2 } ) x 3 y 3 = ( x y) ( x 2 − x y y 2) Use the distributive property to multiply xy by x^ {2}xyy^ {2} and combine like terms
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(xyz)^3 (x y z) (x y z) (x y z) We multiply using the FOIL Method x * x = x^2 x * y = xy x * z = xz y * xSince, x 3 3 x 2 y 3 x y 2 y 3 = (x y) 3 Let's factorize another polynomial This has both positive and negative terms, so it can be compared with the expansion of ( x − y ) 3Xy=5;xy=3 Simple and best practice solution for xy=5;xy=3 Check how easy it is, to solve this system of equations and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the system of equations solver your own
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A 3 a 2 b ab 2ba 2b 2 ab 3 = a 3 (a 2 bba 2)(ab 2b 2 a)b 3 = a 3 0 0b 3 = a 3b 3 Check x 3 is the cube of x 1 Check y 3 is the cube of y 1 Factorization is (x y) • (x 2 xy y 2) Trying to factor a multi variable polynomial 12 Factoring x 2 xy y 2 Try to factor this multivariable trinomial using trial andExplanation When ( x, y) ≠ 0 (x, y)\ne 0 ( x, y) = 0 , f ( x, y) = x 3 y − x y 3 x 2 y 2 f (x, y) = \dfrac {x^3yxy^3} {x^2y^2} f ( x, y) = x 2 y 2 x 3 y − x y 3 Partial differentiate with respect to x x x We will use Quotient Rule2xy=3 Geometric figure Straight Line Slope = 4000/00 = 00 xintercept = 3/2 = yintercept = 3/1 = Rearrange Rearrange the equation by subtracting what is
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Making Equivalent Fractions 33 Rewrite the two fractions into equivalent fractions Two fractions are called equivalent if they have the same numeric value For example 1/2 and 2/4 are equivalent, y/ (y1)2 and (y2y)/ (y1)3 are equivalent as well To calculate equivalent fraction , multiply the Numerator of each fraction, by itsGiven, 3 x − y = 2 7 and 3 x y = 2 4 3 3 x − y = 3 3 3 x y = 3 5 As bases are equal powers must be equal x − y = 3 and x y = 5 Adding them, x − y x y = 8 2 x = 8 x = 4 Thus, 4 − y = 3Click here👆to get an answer to your question ️ Using the identity and proof x^3 y^3 z^3 3xyz = (x y z)(x^2 y^2 z^2 xy yz zx)
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x^3 3x^2y 3xy^2y^3 (x y)^3 Solution Well you can use many methods to simplify like Using Pascal Triangle which give be 1, 3, 3, 1 as the expansion You can simplify (x y)^3 to either (x y) (x y) (x y) or (x y)^2 (x y) But using those two will result in same answer which will be in this format > 1, 3, 3, 1 Hence rArr (x y)^3 = (x y) (x y) (x y) (x y) (x y) (x(xy)3(xy)3 Final result 2y • (3x2 y2) Step by step solution Step 1 11 Evaluate (xy)3 = x33x2y3xy2y3 12 Evaluate (xy)3 = x33x2y3xy2y3 Step 2 Pulling out Explanation ∴ d dx (x3 y3) = d dx (2xy) ∴ d dx x3 d dx y3 = 2 d dx (xy) &, by, the Product Rule, d dx (xy) = x ⋅ d dx (y) y ⋅ d dx (x) = x dy dx y ⋅ 1 Therefore, 3x2 3y2 dy dx = 2(x dy dx y) ∴ dy dx = 2y −3x2 3y2 −2x
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Factor x^3y^3 x3 − y3 x 3 y 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = x a = x and b = y b = y (x−y)(x2 xyy2) ( x y) ( x 2 x y y 2)Polar plot r = exp(sin(theta)) 2Simple and best practice solution for x/y=2/3 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,
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#(xy)^3=(xy)(xy)(xy)# Expand the first two brackets #(xy)(xy)=x^2xyxyy^2# #rArr x^2y^22xy# Multiply the result by the last two brackets #(x^2y^22xy)(xy)=x^3x^2yxy^2y^32x^2y2xy^2# #rArr x^3y^33x^2y3xy^2#Click here👆to get an answer to your question ️ Verify that x^3 y^3 z^3 3xyz = 1/2(x y z)(x y)^2 (y z) (z x)^2Simple and best practice solution for x^33x^2y3xy^2y^3= equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework
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Use the binomial cube formula, a^{3}3a^{2}b3ab^{2}b^{3}=\left(ab\right)^{3}, where a=x and b=yStep 1 write given equations x 5y = 33 (1) and (x y ) / (x y) = 13/3(2) step 2 from 2nd equation x y and 13 are numerators and x y and 3 areTrigonometry Expand (xy)^3 (x y)3 ( x y) 3 Use the Binomial Theorem x3 3x2y3xy2 y3 x 3 3 x 2 y 3 x y 2 y 3
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Click here👆to get an answer to your question ️ If (3)^x y = 81 and (81)^x y = 3 , then the values of x and y areA 3a 2 b ab 2 ba 2b 2 a b 3 = a 3 (a 2 bba 2)(ab 2b 2 a) b 3 = a 3 0 0 b 3 = a 3 b 3 Check x 3 is the cube of x 1 Check y 3 is the cube of y 1 Factorization is (x y) • (x 2 xy y 2) Trying to factor a multi variable polynomial 12 Factoring x 2 xy y 2 Try to factor this multivariable trinomial usingXy=0,x2y3=0 In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other xxy2y3=0 Subtract x2y3=0 from xy=0 by subtracting like terms on each side of the equal sign y2y3=0
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XY=XY=3 No real solutions Sinceif we put y=3/x in xy=3, we get x3/x =3 => (x^2 3)/x =3 => x^2 3x 3 =0 x comes out to be (3sqrt (3)*i)/2 and (3sqrt (3)*i)/2 Hence corresponding values of y are (3sqrt (3)*i)/2 and (3sqrt (3)*i)/2 In both cases, x and y are complex 555 views In this math video lesson I show the student how to graph the equation xy=3 This equation is in standard form and I covert that to slope intercept form toAdd 3 3 to both sides of the equation x = 3 x = 3 x = 3 x = 3 xintercept (s) in point form xintercept (s) ( 3, 0) ( 3, 0) xintercept (s) ( 3, 0) ( 3, 0) Find the yintercept Tap for more steps To find the yintercept (s), substitute in 0 0 for x x and solve for y y
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Factor (xy)^3 (xy)^3 (x y)3 − (x − y)3 ( x y) 3 ( x y) 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = xy a = x y and b = x− y b = x ySolution for xy2xy=3 equation Simplifying x y 2xy = 3 Reorder the terms x 2xy y = 3 Solving x 2xy y = 3 Solving for variable 'x' Move all terms containing x to the left, all other terms to the rightTranscribed image text Using linear approximation of f(x,y)=xy at (3,2), the value of f(29,19) estimated to be Xy 1111 Previous question Next question Get more help from Chegg
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